@user7348, I'm not clear how such a calculation would be done. The standard way in dBB is to "piggyback" on normal QM. The way it goes is as follows. Suppose you want to know position of the particle, when it hits a detector, say. It's guided there by the pilot wave with its classical portion and the quantum potential. First you assume the particle starts in a certain probabilistic distribution called "equilibrium" which has the property of satisfying Born probability. Then you look how it will behave under the influence of the pilot wave. You notice that its position, as it evolves, will still be given by Born probability applied to the pilot wave! As shown by the equivalence theorem. You can consider detailed trajectories as much as you want - you'll still come up with this fact. So, naturally, you just do the standard QM calculation (psi norm gives probability) and you're done. Even if standard QM never existed, this would still be the natural and easiest approach in dBB.

That's for position. Similar considerations apply for other observables, equivalence has been shown for all of them (AFAIK).

So it's not clear to me what you're asking for. One possibility is, when the calculating scientists gets to the place where he'd like to invoke the equivalence theorem, don't. Instead insert its proof; then go ahead and use it. That would, perhaps, make it more of a calculation "from the framework of dBB"?

Please outline, just roughly, how you imagine the dBB calculation should go. Then we can see how it differs from the normal, easy way via equivalence theorem.

That's for position. Similar considerations apply for other observables, equivalence has been shown for all of them (AFAIK).

So it's not clear to me what you're asking for. One possibility is, when the calculating scientists gets to the place where he'd like to invoke the equivalence theorem, don't. Instead insert its proof; then go ahead and use it. That would, perhaps, make it more of a calculation "from the framework of dBB"?

Please outline, just roughly, how you imagine the dBB calculation should go. Then we can see how it differs from the normal, easy way via equivalence theorem.